simplify code

if statement is always true at this point, so remove it.
This commit is contained in:
Sven Nierlein 2023-03-27 12:59:53 +02:00
parent bf82700078
commit 6e64973a44

View file

@ -1179,10 +1179,7 @@ multiply (char *str)
val = strtod (str, &endptr);
if ((val == 0.0) && (endptr == str)) {
if(multiplier != 1) {
die(STATE_UNKNOWN, _("multiplier set (%.1f), but input is not a number: %s"), multiplier, str);
}
return str;
die(STATE_UNKNOWN, _("multiplier set (%.1f), but input is not a number: %s"), multiplier, str);
}
if(verbose>2)